X^2-12x=160

Solution for X^2-12x=160 equation:

X^2-12X=160

We move all terms to the left:

X^2-12X-(160)=0

a = 1; b = -12; c = -160;
Δ = b2-4ac
Δ = -122-4·1·(-160)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*1}=\frac{-16}{2}
=-8
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*1}=\frac{40}{2}
=20
$